Problem Description Given a linked list, remove nth node from end of list and return its head. The list can have various sizes, and the node we need to remove can be anywhere from the beginning to the end of the list. Approach To solve this problem efficiently, we need to think about how to … Read more
The 4Sum problem is a variation of the classic two-sum problem. The task is to find all unique quadruplets in an array that sum up to a target value. This problem is often encountered in coding interviews and algorithm competitions. In this blog post, we will discuss various solutions for the 4Sum problem, ranging from … Read more
The 3Sum Closest problem from Leetcode is a popular algorithmic challenge that tests your understanding of array manipulation and optimization techniques. In this article, we’ll cover the problem statement, a step-by-step approach to solving it, and explain multiple solutions from naive to optimized with their complexities. We’ll also provide well-commented Java code for each solution. … Read more
Finding the median of two sorted arrays is a classic problem in computer science and competitive programming. It is particularly interesting due to its constraints, which encourage an efficient solution rather than a simple brute-force approach. In this article, we’ll cover different methods to solve this problem, including their pros and cons, and provide Java … Read more
In this article, we will explore the Two Pointer pattern in detail. We’ll discuss what it is, when to use it, and go through some classic examples to illustrate how powerful it can be. What is the Two Pointer Technique in Coding? The Two Pointer technique is a pattern where two pointers (or indices) are … Read more
Problem Description: Given n non-negative integers representing an elevation map where the width of each bar is 1, compute how much water it can trap after raining. Example 1 : Example 2: Constraints: Problem Link :Trapping Rain Water – LeetCode Solution(s): Approach 1: Brute Force Solution Java Code: Explanation: 1.Initialization: 2.Main Loop: 3.Finding Maximum Height to the Left: … Read more